Construct a triangle PQR in which QR = 6 cm, ∠Q = 60° and PR − PQ = 2 cm

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#### Solution

The below given steps will be followed to construct the required triangle.

Step I:- Draw line segment QR of 6 cm. At point Q, draw an angle of 60°, say ∠XQR.

Step II:- Cut a line segment QS of 2 cm from the line segment QT extended in the opposite side of line segment XQ. (As PR > PQ and PR - PQ = 2 cm). Join SR.

Step III:- Draw perpendicular bisector AB of line segment SR. Let it intersect QX at point P. Join PQ, PR.

ΔPQR is the required triangle.

Concept: Some Constructions of Triangles

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